Re: A83: Tutorials...


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Re: A83: Tutorials...




Joe Wingbermuehle wrote:

> Isn't it 360 because 6!/2!=360 ?

It would be if you could have any digit in any position.  But the one catch is
that the number must be odd, therefore limiting the last digit to either 1, 3,
or 5.

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Bryan Rabeler <brabeler@ticalc.org>
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