Re: A83: Tutorials...
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Re: A83: Tutorials...
That is the right way.
> don't you pay too much attention to those 1s now? First you say that
> only 3 digits can be the rightmost digit. Then when you've calculated the
> number of possible combinations, you divide that number by two. But by then
> you've already reduced the number of possible combinations once! I'd say 4
> digits can be in the units place (3, 1, 5 and 1), then calculate
5*4*3*2*1*
> 4
> = 480. _This_ number should be halved -> 240 possible combinations.
>
> Am I completely wrong?
>
> Linus
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