Re: A83: Tutorials...


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Re: A83: Tutorials...





>> PPS:  I failed my math final :)...there was a question on "mutual
>> exclusive"...if you have the number 341521 how many ways can you make a
odd
>> number if you re-arrange numbers.  360...please say 360 :)...
>
>There are 3 different odd numbers in that 6 digit number, so there are 3
>possibilites for the last place value.  The other place values don't
matter.
>So there are 5 posibilites for the first place value, 4 for the second, 3
for
>the third, 2 for the fouth, 1 for the fith, and 3 for the last one.
>5*4*3*2*1*3 = 360.  But since there are two 1's, you must divide that by 2
>because you could swap the 1's and you would get the same number.  So I
think
>the answer should be 180.

the sample space would still have those two 1s in there so i think it should
be 360


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